oddballs: send usage() help text to standard output
Using the show_usage_if_asked() helper we introduced earlier, fix callers of usage() that want to show the help text when explicitly asked by the end-user. The help text now goes to the standard output stream for them. The callers in this step are oddballs in that their invocations of usage() are *not* guarded by if (argc == 2 && !strcmp(argv[1], "-h") usage(...); There are (unnecessarily) being clever ones that do things like if (argc != 2 || !strcmp(argv[1], "-h") usage(...); to say "I know I take only one argument, so argc != 2 is always an error regardless of what is in argv[]. Ah, by the way, even if argc is 2, "-h" is a request for usage text, so we do the same". Some like "git var -h" just do not treat "-h" any specially, and let it take the same error code paths as a parameter error. Now we cannot do the same, so these callers are rewrittin to do the show_usage_and_exit_if_asked() first and then handle the usage error the way they used to. Acked-by: Jeff King <peff@peff.net> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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@@ -26,6 +26,9 @@ static char *create_temp_file(struct object_id *oid)
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return path;
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}
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static const char usage_msg[] =
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"git unpack-file <blob>";
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int cmd_unpack_file(int argc,
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const char **argv,
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const char *prefix UNUSED,
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@@ -33,8 +36,9 @@ int cmd_unpack_file(int argc,
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{
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struct object_id oid;
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if (argc != 2 || !strcmp(argv[1], "-h"))
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usage("git unpack-file <blob>");
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show_usage_if_asked(argc, argv, usage_msg);
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if (argc != 2)
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usage(usage_msg);
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if (repo_get_oid(the_repository, argv[1], &oid))
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die("Not a valid object name %s", argv[1]);
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