2023-03-25 03:58:02 +03:00
|
|
|
|
#include <string.h>
|
|
|
|
|
|
|
|
|
|
|
|
/*
|
|
|
|
|
|
* Вернуть длину строки.
|
|
|
|
|
|
* Строки в C -- это массив символов, в конце которого находится нулевой символ ( '\0')
|
|
|
|
|
|
*/
|
|
|
|
|
|
int
|
|
|
|
|
|
mystrlen(const char *s)
|
|
|
|
|
|
{
|
2025-12-04 23:55:35 +03:00
|
|
|
|
int len = 0;
|
|
|
|
|
|
while (s[len] != '\0') {
|
|
|
|
|
|
len++;
|
|
|
|
|
|
}
|
|
|
|
|
|
return len;
|
2023-03-25 03:58:02 +03:00
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
|
|
/*
|
|
|
|
|
|
* Найти индекс, с которого строка s2 присутствует в строке s1
|
|
|
|
|
|
* или -1
|
|
|
|
|
|
*/
|
|
|
|
|
|
int
|
|
|
|
|
|
mystr_idx(const char *s1, const char *s2)
|
|
|
|
|
|
{
|
2025-12-04 23:55:35 +03:00
|
|
|
|
if (s1 == NULL || s2 == NULL)
|
|
|
|
|
|
return -1;
|
|
|
|
|
|
|
|
|
|
|
|
if (s2[0] == '\0')
|
|
|
|
|
|
return 0;
|
|
|
|
|
|
|
|
|
|
|
|
int len1 = mystrlen(s1);
|
|
|
|
|
|
int len2 = mystrlen(s2);
|
|
|
|
|
|
|
|
|
|
|
|
if (len2 > len1)
|
|
|
|
|
|
return -1;
|
|
|
|
|
|
|
|
|
|
|
|
for (int i = 0; i <=len1 - len2; i++) {
|
|
|
|
|
|
int j = 0;
|
|
|
|
|
|
while (j < len2 && s1[i + j] == s2[j]) {
|
|
|
|
|
|
j++;
|
|
|
|
|
|
}
|
|
|
|
|
|
if (j == len2)
|
|
|
|
|
|
return i;
|
|
|
|
|
|
}
|
|
|
|
|
|
|
2023-03-25 03:58:02 +03:00
|
|
|
|
return -1;
|
|
|
|
|
|
}
|
|
|
|
|
|
|
2025-12-04 23:55:35 +03:00
|
|
|
|
|
|
|
|
|
|
|